How to add digits to a long value

Question

So I have this variable long hashvalue and I want to add digits to it if something is true.

I have this array int arr[3][3] with the numbers -1, 1, 0, 0, -1, 1, 0, 0, -1 in it

I need something like this:

if(array[i][j] == -1){ //add digit 2 to hashvalue } else if(array[i][j] == 1){ //add digit 1 to hashvalue } else if(array[i][j] == 0){ //add digit 0 to hashvalue }

hashvalue = 210021002

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– Elliott Frisch, Commented Jul 12, 2015 at 20:35

Para Black · Accepted Answer · 2015-07-12 20:38:06Z

You can simply make a string for the hashvalue and adding the digits to the string via the + (or +=) operator. To receive a long object from the string, you can use the Long.parseLong() function.

String hashvalue = ""; // Add your digits to the String here hashvalue += "1"; // Convert the String to a long long finalHashvalue = Long.parseLong(hashvalue);

João Neves · Accepted Answer · 2015-07-12 20:46:09Z

you can just multiply hashvalue by 10 and then add the wanted digit. Like:

if(array[i][j] == -1){ hashValue = hashValue * 10 + 2; } else if(array[i][j] == 1){ hashValue = hashValue * 10 + 1; } else if(array[i][j] == 0){ hashValue = hashValue * 10 + 0; }

Imagine your hashValue starts with 3, if you multiply it by 10 it becomes 30, if you add the digit, let's say 2, it becomes 32. The digit has been added. I hope I helped!

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