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PHP NOOB, i have been working on this code all day, but cant find any good way to fix it.

here is my code:

$priv = explode(',', '0,1,1'); $m = 'me'; for($i = 0; $i <= 2; $i++) { if($priv[$i] == '0') { $m.$i = 20; } else { $m.$i = 10; } }

Am trying to join $m.$i together and set it to 20 or 10, but i end up having me20 or me10 instead of me1 = 20 or me1 = 10 when i echo $m.$i which is legit, is there anyways to make this work?

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  • 1
    when i echo $k.$m which is legit Where is $k? Commented Oct 4, 2015 at 8:35
  • Ahh, its okay and now I think you meant me0 = 20 ? Commented Oct 4, 2015 at 8:38

3 Answers 3

Reset to default
5

$m.$i = 20;

This will assign $i = 20 and then concatenate it with $m and hence you will see me20.

What you need is $m . $i .= 20; instead. which will concatenate them altogether.

Fixed:

<?php $priv = explode(',', '0,1,1'); $m = 'me'; for($i = 0; $i <= 2; $i++) { if($priv[$i] == '0') { echo $m . $i .= 20; } else { echo $m.$i .= 10; } } ?>

EDIT:

The above answer was a total misunderstanding, I realised you intended to create the variables:

for($i = 0; $i <= 2; $i++) { if($priv[$i] == '0') { ${$m.$i} = 20; echo $me0; } else { ${$m.$i} = 10; } }
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2 Comments

i want $m0 = 20 or $m0 = 10
@ChrysUgwu Ahh Crap.. I just realized. fixing it in a minute.
2

Assign it like so. 

${$m.$i} = 20;
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1

You are trying to dynamically create variables, so you have to do something like this:

$priv = explode(',', '0,1,1'); $m = 'me'; for($i = 0; $i <= 2; $i++) { if($priv[$i] == '0') { ${$m.$i} = 20; } else { ${$m.$i} = 10; } }

then try to priny $me0, $me1

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