Python Decorator accessing self [duplicate]

Question

Here's an example method that's inside a Python Class:

def publish_aggregate_account_group_stats(self, account_group_token): message = { "type": "metrics-aggregate-account-group-stats", "accountGroupToken": account_group_token } try: self._get_writer().write(message) except: self._put_cache(message)

There is a handful of methods in my class that all run the try/except, that I think could be DRYed up or cleaned up by simply creating a decorator that handles that for me. I'm just unsure how the decorator would look/work by accessing self.

acushner · Accepted Answer · 2015-10-26 18:06:10Z

something like this will work:

from contextlib import contextmanager class Test(object): def __init__(self): self.j = set() @contextmanager def handle_exc(self, msg): try: yield except: print('adding to internal structure:', msg) self.j.add(msg) def test(self): m = 'snth' with self.handle_exc(m): raise Exception('error')

a decorator is tough to use here because you're creating values within the function itself, so the outside decorator will never know about them unless you find a way to propagate them up (via a certain exception or something.)

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