Is it possible to use 'if-case' in place of a switch that has a coma delimited list as a case?

Question

Swift 2 introduced if-case which is supposed to be a more terse way of expressing a switch that only has a few cases. I'm wondering if there is a way of expressing a switch statement with a comma delimited list as an if-case.

let (a,b) = (1,0) switch (a,b) { case (1,0), (0,1), (1,1): print("true") default: print("false") }

What I've tried:

if case (a,b) = (1,0) { // works } if case (a,b) = (1,0), (0,1), (1,1) { // doesn't }

This compiles but returns false for the (a,b) tuple:

if case (a,b) = (1,0), case (a,b) = (0,1), case (a,b) = (1,1) { print("if case true") } else { print("if case false") }

What I'd like to see:

I'd like to see an approach to shorten the above switch statement into a single if-case.

My Question

Is it possible to use if-case in place of a switch that has a coma delimited list as a case?

Dan Beaulieu · Accepted Answer · 2016-02-11 03:36:34Z

Well, after nearly a month. This is the closest I could get to satisfying the comma delimited list question. This actually satisfies the same requirement but in a different way.

let tuple = (1,0) if case (0...1, 0...1) = tuple where !(a == 0 && b == 0) { return true } else { return false }

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