CoreMIDI app not showing in other software

Question

I am playing around a bit with CoreMIDI in Swift on OSX, and got most of the things to work properly.

The only issue I have now is that my app is not seen by other software and apps and an available input/output. This is the case for in GarageBand, MIDIMonitor and the VVMidi test apps.

I tried multiple things, including this which seems to be the correct approach :

let clientCreateResult = MIDIClientCreate("MIDIApp", { (notification, _) -> Void in print("Configuration Changed") }, nil, &midiClient) if (clientCreateResult != noErr) { printError(clientCreateResult) return; } let inputCreateResult = MIDIInputPortCreateWithBlock(midiClient, "MIDIApp In", &inputPort, MyMIDIReadBlock) if (inputCreateResult != noErr) { printError(inputCreateResult) return; } let outputCreateResult = MIDIOutputPortCreate(midiClient, "MIDIAPP Out", &outputPort) if (outputCreateResult != noErr) { printError(inputCreateResult) return; }

Sadly no luck. I'm not sure what I'm doing wrong, I tried reproducing the exact same code as existing frameworks with no significant result.

I could really use some pointers as of why my app isn't listed in other ones.

Thanks!

Gene De Lisa · Accepted Answer · 2016-05-05 00:31:51Z

3

Create a virtual destination. See the docs for MIDIDestinationCreateWithBlock

answered May 5, 2016 at 0:31

Gene De Lisa

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3 Comments

Kurt Revis Over a year ago

That makes your app appear as an input in other apps. Use MIDISourceCreate if you want your app to also be an output that other apps can connect to. More details in this answer..

Gene De Lisa Over a year ago

True. I wasn't exactly sure what the OP wanted. Your linked answer is more complete.

Ashamed question Over a year ago

Well, I can't believe I missed that... It works just great, I was sure I tried this, I guess I messed up the code and just moved on. Thank you so much!

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