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>>> df['X'].head() 0 25+4 1 25+5 2 15+3 3 20+2 4 20+3 Name: X, dtype: object

How do I evaluate this so my dataframe is this:

>>> df['X'].head() 0 29 1 30 2 18 3 22 4 23 Name: X, dtype: int64
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    A word of warning: evaling arbitrary Python code is potentially dangerous, especially if the code comes from an external source that you cannot 100% trust. Remember Little Bobby Tables. Commented May 7, 2016 at 2:59

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Although there are security concerns, you can use eval to evaluate each element using a lambda expression.

df = pd.DataFrame({'X': ['25+4', '25+5', '15+3', '20+2', '20+3']}) >>> df X 0 25+4 1 25+5 2 15+3 3 20+2 4 20+3 >>> df.X.apply(lambda x: eval(x)) 0 29 1 30 2 18 3 22 4 23 Name: X, dtype: int64

For a description of security concerns, see:

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