Is there something wrong if I use or not "use strict" mode in JS?

Question

I am working on a Gulp file and I just set JSHint, I see this option in the .jshintrc file:

"strict" : true

then I went to my files I put this at the very beginning:

'use strict'; angular.module('MyApp', ['ngRoute']) .config(function($locationProvider, $routeProvider) {. . .});

and I now I am getting a new error

public/app.js line 1 col 1 Use the function form of "use strict".

so I did:

angular.module('MyApp', ['ngRoute']) .config(function($locationProvider, $routeProvider) { 'use strict'; return { . . . } });

and the error its gone.

So, what is the difference here and what is wrong if I don't use the strict mode?

See What does “use strict” do in JavaScript, and what is the reasoning behind it? and JSLint is suddenly reporting: Use the function form of “use strict” — Oriol
– Oriol, Commented May 8, 2016 at 23:25

jdphenix · Accepted Answer · 2016-05-08 23:15:28Z

JSHint by default doesn't allow you to have 'use strict'; at a global scope when set to true, because it will interfere with Javascript libraries and legacy code that isn't designed for strict mode in mind.

Use

strict: 'global'

if you want to be able to do that.

or

strict: false

if you do not want to lint code to require strict mode.

strict option reference for JSHint

Oh, I see. developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/… This tells you how strict mode behaves

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