Echo statement printing the value '1'

Question

When I wanted to test whether the value is properly passed from HTML form to PHP, I found something is wrong with the echo statement. Here is the HTML text box code

<div class = form-group> <label for = 'bcaa'>BCAA 5gms Cost</label> <input type = 'text' class = 'form-control' name = 'bcaa'> </div>

And here is the PHP code to get the value and print it simply.

<?php $bcaacost = isset($_POST['bcaa']) ; echo $bcaacost; ?>

The value given in the text box is not printed, but simply '1' is printed the more echo statement is added more no of '1' is printed

Like

echo "something"; echo "blah blah";

The output is

What's the reason for this and what do I need to do to fix this?

The result of an isset is a boolean TRUE or FALSE. That should be all you need to know — RiggsFolly
– RiggsFolly, Commented May 10, 2016 at 11:25

Gopal Joshi · Accepted Answer · 2016-05-10 11:26:35Z

Remove isset() for variable assigning as it checks veriable $_POST['bcaa'] is set or not.

$bcaacost = $_POST['bcaa'];

Full code

<?php $bcaacost = $_POST['bcaa']; echo $bcaacost; ?>

Read more about isset()

Sougata Bose · Accepted Answer · 2016-05-10 11:26:10Z

isset() returns true or false depending on the variable set or not.

$bcaacost = isset($_POST['bcaa']) ; // return true / 1 echo $bcaacost; // prints 1

it should be like -

if(isset($_POST['bcaa'])) { echo $_POST['bcaa']; }

Or if you want to print some default, then -

$bcaacost = isset($_POST['bcaa']) ? $_POST['bcaa'] : 'Default'; echo $bcaacost;

Nana Partykar · Accepted Answer · 2016-05-10 11:27:41Z

if(isset($_POST['bcaa'])) { $bcaacost = $_POST['bcaa'] ; echo $bcaacost ; }

Otherwise, isset($_POST['bcaa']) will print 1 or 0

RiggsFolly · Accepted Answer · 2016-05-10 11:28:04Z

isset() checks that a variable exists, and returns either true(1) or false(0)

To see the contents of $_POST['bcaa'] you need to check it exists i.e. isset() but then use the contents of the variable

<?php $bcaacost = isset($_POST['bcaa']); if ( $bcaacost ) { echo $_POST['bcaa']; } ?>

Or more simply

if ( isset($_POST['bcaa']) ) { echo $_POST['bcaa']; }

As to your suggestion that :

echo "something"; echo "blah blah";

will create 11 that cannot be so. Something else must be causing this or you are just confused as to what is creating the 11 output

Ranjit Shinde · Accepted Answer · 2016-05-10 11:28:07Z

the result of isset is true or false. In your case the result is true and it assigned back to $bcaacost and that's why it echoing 1.

use following code:

<?php $bcaacost = isset($_POST['bcaa'])?$_POST['bcaa']:"not set"; echo $bcaacost; ?>

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