python delayed loop without new line waits until loop is finished to display text [duplicate]

Question

I have a loop in python that is sleeping 0.1 seconds every iteration. It is sequentially printing out a string to the console. I want it to add a character every iteration, But the problem is that it waits until the loop is finished to display the text. This only happens when I have the ", end='' " bit at the end of the print call.

import time def speak(text): i = 0 for i in range(0, len(text) + 1): print(text[i], end='') i += 1 time.sleep(0.1) speak("Test 123. Can you see me?")

Add the flush parameter to the print function to get it to print immediately: print(text[i], end='', flush=True) — Carl Groner
– Carl Groner, Commented Jul 15, 2016 at 0:42

user94559 · Accepted Answer · 2016-07-15 00:45:17Z

As the comments say, you need flush=True in your call to print(...).

Also, your loop goes one character off the end of the string (causing an exception), and it would be nice to print a newline at the end of the text. Here's a fixed up version that works on my machine:

import time def speak(text): for c in text + '\n': print(c, end='', flush=True) time.sleep(0.1) speak("Test 123. Can you see me?")

Thank you! I'm kinda new to python. I love how fast this community responds to questions!

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