add 0 to hours/minutes under 10 [duplicate]

Question

i've some issue to found a proper solution in swift3 to do this :

I have a date like 10h20m. When my hours are under 10 it will be "5h30". I want to out "05h30".

class func getTime(_ user: SUser) -> String { let currentDate = Date() let firstDate = user.firstDate let difference = firstDate?.timeIntervalSince(now) let hours = String(Int(difference!) / 3600) let minutes = String(Int(difference!) / 60 % 60) let time = "\(hours)h\(minutes)m" return time }

if someone have an idea how do that simply et properly thank you !

Consider DateComponentsFormatter

vadian
– vadian

2016-11-09 17:34:13 +00:00
Commented Nov 9, 2016 at 17:34 — vadian
– vadian, Commented Nov 9, 2016 at 17:34

Community · Accepted Answer · 2017-05-23 12:13:41Z

You can do something like this

class func getTime(_ user: SUser) -> String { let currentDate = Date() let firstDate = user.firstDate let difference = firstDate?.timeIntervalSince(now) let hours = String(Int(difference!) / 3600) if Int(hours)! < 10 { hours = "0\(hours)" } var minutes = String(Int(difference!) / 60 % 60) if Int(minutes)! < 10 { minutes = "0\(minutes)" } let time = "\(hours)h\(minutes)m" return time }

or a better way

class func getTime(_ user: SUser) -> String { let currentDate = Date() let firstDate = user.firstDate let difference = firstDate?.timeIntervalSince(now) let hours = Int(difference!) / 3600 let minutes = Int(difference!) / 60 % 60 let time = "\(String(format: "%02d", hours))h\(String(format: "%02d", minutes))m" return time }

Suggested here - Leading zeros for Int in Swift

Eeshwar · Accepted Answer · 2016-11-09 17:32:12Z

class func getTime(_ user: SUser) -> String { let currentDate = Date() let firstDate = user.firstDate let difference = firstDate?.timeIntervalSince(now) var hours = String(Int(difference!) / 3600) if ((Int(difference!) / 3600)<10) { hours = "0\(hours)" } var minutes = String(Int(difference!) / 60 % 60) if ((Int(difference!) / 60 % 60)<10) { minutes = "0\(minutes)" } let time = "\(hours)h\(minutes)m" return time }

Scriptable · Accepted Answer · 2016-11-09 17:34:43Z

I think you would be better off with a simple formatting function that you can call inline.

Try something like

func formatHour(hour:Int) -> String { return (String(hour).characters.count == 1) ? "0\(hour)" : "\(hour)" } let hour = 5 print("\(formatHour(hour: hour))") // output "05"

You can adjust this as needed, maybe pass the string in instead and save doing the conversion in the function. could also add a guard statement to ensure that the number is within the bounds of hours, or a string is less than three characters etc.

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