how to input string, output int, use array python

Question

Someone can help me to complete this source code am input String, change to array list, and output that int in that table

x = input() y = list(x) table = {" ":270, "a":0, "b":90, "c":180, "d":270, "e":0, "f":90, "g":180, "h":270, "i":0, "j":90, "k":180, "l":270, "m":0, "n":90, "o":180, "p":270, "q":0, "r":90, "s":180, "t":270, "u":0, "v":90, "w":180, "x":270, "y":0, "z":90,} for i in range(len(y)): print(y[i]) print("{["+y[i]+"]}".format(table))

Error at

print("{["+y[i]+"]}".format(table))

Example: for input abc the expected output should be:

a 0 b 90 c 180

You should add an input example and the desired output. See stackoverflow.com/help/mcve — Riccardo Petraglia
– Riccardo Petraglia, Commented Nov 16, 2016 at 9:01
range(len(y)) will fail because indexes of lists start at 0 not at 1. — Torxed
– Torxed, Commented Nov 16, 2016 at 9:02

Serge Ballesta · Accepted Answer · 2016-11-16 14:08:10Z

2

The . has higher priority that the string concatenation +.

This expression "{["+y[i]+"]}".format(table) is actually evaluated as:

"{["+y[i]+("]}".format(table))

which is not what you want.

You must use parenthesis to force the concatenation before applying format method:

print(("{["+y[i]+"]}").format(table))

BTW, I assume that it was a simplified example, because using format here is really overkill, as this would produce the same output:

for c in y: print(c) print(table[c])

edited Nov 16, 2016 at 14:08

answered Nov 16, 2016 at 9:08

Serge Ballesta

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4 Comments

Bagus Prasetyo W Over a year ago

thanks sir.. always use parenthesis before format method. btw iam still newbie

Guillaume Over a year ago

Explanation is accurate, and that works... in the sense that it produces the expected output. But using a .format() to fetch a mapped value from a dict... that it about the most horrible way to do it.

Serge Ballesta Over a year ago

@Guillaume: I assumed it was a simplified example to demonstrate a problem... Anyway I've edited my post :-)

Bagus Prasetyo W Over a year ago

@Guillaume : sir , why iam include new array (int), i change "a":0,"b":90, "c":180, to "1":0, "2":90, "3":180 error at from array(0) (from ealry) wheter use int can't in array list?

Axel Juraske · Accepted Answer · 2016-11-16 09:04:54Z

I‘m not sure what you want to do. But maybe something like this?

for i in y: print(i, table[i])

Guillaume · Accepted Answer · 2016-11-16 09:09:01Z

This code fails and is far from elegant:

y = list(x) for i in range(len(y)): print(y[i]) print("{["+y[i]+"]}".format(table))

In Python you generally don't need to do C style iteration over a string, using a incrementing index. Just iterate over the string directly:

for letter in x: print("my letter is", letter) print("my integer is", table[letter])

And to convert each letter to the matching integer, generating a list, then printing it:

my_int_list = [table[letter] for letter in x] print(my_int_list)

Last remark, you should name your variables with descriptive names, x and y are more than confusing.

user2393256 · Accepted Answer · 2016-11-16 09:02:29Z

If i understood you correctly you wanted to convert every element in y to int. You can use list comprehension for that:

y = [int(x) for x in y]

Jacek Zygiel · Accepted Answer · 2016-11-16 09:55:21Z

I think that answer for your question will be this code:

x = str(input('Input string\n')) table = {" ": 270, "a": 0, "b": 90, "c": 180, "d": 270, "e": 0, "f": 90, "g": 180, "h": 270, "i": 0, "j": 90, "k": 180, "l": 270, "m": 0, "n": 90, "o": 180, "p": 270, "q": 0, "r": 90, "s": 180, "t": 270, "u": 0, "v": 90, "w": 180, "x": 270, "y": 0, "z": 90} for element in x: if element in table: print '{}\n{}'.format(element, int(table[element]))

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