Call Flask API with AJAX

Question

I am experimenting with Flask and AJAX, I have a simple API route here , hosted at OpenShift. I want to call the API in a Javascript file with Ajax. The OpenShift Python file is simple:

from flask import Flask app = Flask(__name__) import json @app.route('/hello/<name>') def hello_world(name=None): str = {'key':'Hello World!', 'q':name} #out = {'key':str} res = json.dumps(str) return res if __name__ == '__main__': app.run()

And here is the Ajax call:

$.ajax({ type:"GET", dataType: "json", data:'Payam', url: "http://mypythonapp-spacepirate.rhcloud.com/hello/", success: function(data){ buf1=data; console.log(data); } })

But this makes a call to this url which results in 404. How can I solve this? Just to mention CORS is not an issue.

http://mypythonapp-spacepirate.rhcloud.com/hello/?Payam

Alex G Rice · Accepted Answer · 2016-12-16 20:19:57Z

Try changing your url property to

url: "http://mypythonapp-spacepirate.rhcloud.com/hello/world",

Then you will get a 200 response status, instead of the 404. The reason is the flask route you created has a required parameter after the hello/.

edit: followup to question about using variable for the data

method1: just add encode the parameter to the url

url: "http://mypythonapp-spacepirate.rhcloud.com/hello/" + encodeURIComponent(xyz)
method2: use the data parameter to the ajax call as you have started to do. I think that jquery will translate that into the URL query string for a get, like this. Notice the ? delimiting the start of query string:

http://mypythonapp-spacepirate.rhcloud.com/hello/?xyz

You can verify that by checking in your browser dev tools and seeing what URL the ajax call is actually requesting. Also note that in the flask handler you would then need to check for request.query_string to get the data, because <name> parameter would be empty.

Cool! Please mark my answer as accepted, or upvote my answer, as that is the best way to say 'thanks' on SO.
Just curious, anyway to achieve this also by passing data, and not modifying the url directly?

Community · Accepted Answer · 2017-05-23 12:24:50Z

Using the guidelines provided by Alex G Rice and the answers here Python Flask how to get parameters from a URL? I found out how to pass the data directly as following:

The Ajax call:

$.ajax({ type:"GET", dataType: "json", data:{'name':'Payam'}, url: "http://mypythonapp-spacepirate.rhcloud.com/hello/", success: function(data){ buf1=data; console.log(data); } })

The python file:

@app.route('/hello/', methods=['GET','POST']) def hello_world(name=None): buf1 = request.args.get('name') str = {'key':'Hello World!', 'q':buf1} #out = {'key':str} res = json.dumps(str) return res

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