I use the command: adb devices to list the attached devices. On my computer I get : List of devices attached HT9CTP820988 device
My question is: how can I get this id (HT9CTP820988) programmatically ?
2
- Did you ever figure this out? Doesn't seem like any of the answers are correct.Jens Zalzala– Jens Zalzala2015-09-17 14:20:24 +00:00Commented Sep 17, 2015 at 14:20
- Found the correct answer here: stackoverflow.com/questions/11029294/…Jens Zalzala– Jens Zalzala2015-09-17 14:35:39 +00:00Commented Sep 17, 2015 at 14:35
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6 Answers
What you're seeing with the adb devices command is the serial number:
Serial number — A string created by adb to uniquely identify an emulator/device instance by its console port number. The format of the serial number is -. Here's an example serial number: emulator-5554
(refererence: http://developer.android.com/guide/developing/tools/adb.html)
When you ask "how can I get this id programmatically" what exactly do you mean? From an Android app or from a desktop app?
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How about this one?
http://developer.android.com/reference/android/provider/Settings.Secure.html#ANDROID_ID
edit: Hmm I recall this, it can't be right; the ANDROID_ID is supposed to be 64-bit. Maybe the string you see is given by the USB driver?
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Look at Settings.ACTION_DEVICE_INFO_SETTINGS and answers that have already been given in the past How to find serial number of Android device?
1 Comment
Arutha
String deviceId = Settings.System.getString(getContentResolver(), Settings.System.ANDROID_ID); -> doesn't returns the same ID than adb devices !!
I think the emulator id's purpose is to identify the emulator and devices in the development environment. And it may not be accessible from the phone.
1 Comment
Arutha
The serial number is displayed in the phone settings (menu About Phone | Phone identity) !
It's possible by changing *strings_dev* struct from drivers/usb/gadget/android.c
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I'm Using the following code...
String aid = Settings.Secure.getString(getContext().getContentResolver(), "android_id"); Object obj = null; try { ((MessageDigest) (obj = MessageDigest.getInstance("MD5"))).update( aid.getBytes(), 0, aid.length()); obj = String.format("%032X", new Object[] { new BigInteger(1, ((MessageDigest) obj).digest()) }); } catch (NoSuchAlgorithmException localNoSuchAlgorithmException) { obj = aid.substring(0, 32); } 
1 Comment
Cpp plus 1
In English, "bro" is considered informal. You should probably use "hello" instead.