I want to use int in my array element

Question

I want to use int in my array element. Now my code is

def hanoi_pos(discs, index): power = 2**discs stacks = ['', '', ''] for disc in range(discs): stack = (index+power//2)//power % 3 if disc % 2 == 0: stack = (3 - stack) % 3 power = power // 2 stacks[stack] += chr(64 + discs - disc) return stacks def get_game_state(stacks): return '\n'.join([' '.join(st) if st else '-' for st in stacks]) x = hanoi_pos(4, 6) y = get_game_state(x) print(y)

In my code, I use chr method in the place of chr(64 + discs - disc). But this time, I want to use int like 1,2,3・・・・. "A" corresponds to 1, "B" corresponds to 2, "C" corresponds to 3・・・・. I wrote this place like int(64 + discs - disc),but error happen. I thought for statement can be used, but it is redundant. So, how can I do this? How can I convert str into int?

First if you have an error you should also post the traceback. Second, Python is a strongly typed language. You are trying to append an int to a string and that gives you (I assume) TypeError exception. — bergerg
– bergerg, Commented Jul 29, 2017 at 7:33

Mayur Vora · Accepted Answer · 2017-08-02 04:06:38Z

Hello mikimiki,

Try this below code,

def hanoi_pos(discs, index): power = 2**discs stacks = ['', '', ''] for disc in range(discs): stack = (index+power//2)//power % 3 if disc % 2 == 0: stack = (3 - stack) % 3 power = power // 2 print "--",discs, disc,"--" stacks[stack] += chr(48 + discs - disc) return stacks def get_game_state(stacks): return '\n'.join([' '.join(st) if st else '-' for st in stacks]) x = hanoi_pos(4, 6) y = get_game_state(x) print(y)

I hope my answer is helpful.
If any query so comment please.

Collectives™ on Stack Overflow

I want to use int in my array element

1 Answer 1

Comments

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Linked

Related