I have a variable of type double, I need to print it in upto 3 decimals of precision but it shouldn't have any trailing zeros...
eg. I need
2.5 // not 2.500 2 // not 2.000 1.375 // exactly till 3 decimals 2.12 // not 2.120 I tried using DecimalFormatter, Am i doing it wrong?
DecimalFormat myFormatter = new DecimalFormat("0.000"); myFormatter.setDecimalSeparatorAlwaysShown(false); Thanks. :)
Try the pattern "0.###" instead of "0.000":
import java.text.DecimalFormat; public class Main { public static void main(String[] args) { DecimalFormat df = new DecimalFormat("0.###"); double[] tests = {2.50, 2.0, 1.3751212, 2.1200}; for(double d : tests) { System.out.println(df.format(d)); } } } output:
2.5 2 1.375 2.12 Your solution is almost correct, but you should replace zeros '0' in decimal format pattern by hashes "#".
So it should look like this:
DecimalFormat myFormatter = new DecimalFormat("#.###"); And that line is not necesary (as decimalSeparatorAlwaysShown is false by default):
myFormatter.setDecimalSeparatorAlwaysShown(false); Here is short summary from javadocs:
Symbol Location Localized? Meaning 0 Number Yes Digit # Number Yes Digit, zero shows as absent And the link to javadoc: DecimalFormat
Use NumberFormat class.
Example:
double d = 2.5; NumberFormat n = NumberFormat.getInstance(); n.setMaximumFractionDigits(3); System.out.println(n.format(d));
Output will be 2.5, not 2.500.
