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I've created a c++ project on ubuntu in visual studio code. It launches the program using gdb mode, but does not show anything in Output. When I launch program from console, the output is present. I tried inserting "console" property, but vscode tells me, that it is forbidden (from similar issue with node https://github.com/Microsoft/vscode/issues/30842).

How can I enable vscode to show the output from my program?

{ "version": "0.2.0", "configurations": [ { "name": "(gdb) Launch", "type": "cppdbg", "request": "launch", "program": "${workspaceFolder}/a.out", "args": [], "stopAtEntry": false, "cwd": "${workspaceFolder}", "environment": [], "externalConsole": true, "MIMode": "gdb", "setupCommands": [ { "description": "Enable pretty-printing for gdb", "text": "-enable-pretty-printing", "ignoreFailures": true } ] } ] }
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3 Answers 3

Reset to default
11

You config is correct. The program output should be in the DEBUG CONSOLE.

Menu | Debug Console or Ctrl+Shift+Y.

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5 Comments

Unfortunately, it does not show the data, that program outputs to cout. Just the gdb data. And debugging works correctly - it stops on breakpoints, etc. Maybe it is not possible to achieve printing program output with gdb?
Thanks, I found the terminal window.
Why does it give output in the debug console? How do I shift it to the integrated one? Also, how do I handle input(cin) for debugging? I don't think i can give input in the debug console
@JatinSharma You can. Don't think, just try.
for me it was in the terminal window under "cppdbg: (programname)". Odd because i'm used to the output being under Debug Console under lldb, but there it is.
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The program was launched in external terminal and due to the configuration of my screen I didn't see it. Everything works fine.

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3 Comments

Is such behavior on Windows?
No, I'm using Ubuntu with Unity. Did not try in Windows.
can you elaborate ? how did you access your config ? what parameters had you have to change ?
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Add this line in setting.json in code-runner.executorMap

"cpp": "g++ -o $fileNameWithoutExt $fileNameWithoutExt.cpp && ./$fileNameWithoutExt"
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Please add further context to your answer.
Please add further details to expand on your answer, such as working code or documentation citations.
This is NOT a solution. It will mess up the debug mode, because debug mode will also execute these commands of args.

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