Printing output based of two list

Question

I have a list containing string elements:

movielst = ['A WALK,DRAGONBALL', 'JAMES BOND,MISSION']

and another list that contains integer values:

userlst = [[1,20],[6,7]]

I'm planning to print the output based off both list where the first element in movielst corresponds to the first list in userlst and so on.

Output to get:

Movies: A WALK,DRAGONBALL Users: 1,20 Movies: JAMES BOND,MISSION Users: 6,7

I wrote

for j in range(len(userlst)-1): for i in movielst: print("Movies: " + str(i)) print("Users: " + str(userlst[j]))

But I'm getting:

Movies: A WALK,DRAGONBALL Users: 1,20 Movies: JAMES BOND,MISSION Users: 1,20 #should be 6,7

How do i print the output based off both lists in parallel?

Rakesh · Accepted Answer · 2018-03-17 15:52:35Z

You can use zip

Ex:

movielst = ['A WALK,DRAGONBALL', 'JAMES BOND,MISSION'] userlst = [[1,20],[6,7]] for i in zip(movielst, userlst): print("Movies: {}".format(i[0])) print("Users: {}".format(", ".join(map(str, i[1]))))

Output:

Movies: A WALK,DRAGONBALL Users: 1, 20 Movies: JAMES BOND,MISSION Users: 6, 7

Note:

I have used map to convert int to string for userlst
join to concat the element in userlst to your required format.

dawg · Accepted Answer · 2018-03-17 15:59:04Z

Use zip, join, and format with a comprehension:

>>> print '\n'.join("Movies: {}\nUsers: {}".format(x,y) for x,y in zip(movielst,userlst)) Movies: A WALK,DRAGONBALL Users: [1, 20] Movies: JAMES BOND,MISSION Users: [6, 7]

Or, as stated in comments and if you want double spaced:

>>> print '\n\n'.join("Movies: {}\nUsers: {}".format(*z) for z in zip(movielst,userlst)) Movies: A WALK,DRAGONBALL Users: [1, 20] Movies: JAMES BOND,MISSION Users: [6, 7]

Nice solution. We could again simplify this without unpacking x and y. ie, print('\n'.join("Movies: {}\nUsers: {}".format(*args) for args in zip(movielst,userlst))). But your answer is much more readable.

Nathan · Accepted Answer · 2018-03-17 15:47:21Z

If you know both lists are the same length:

for i in range(len(movielst)): print("Movies: {}".format(str(movielst[i])) print("Users: {}".format(str(userlst[i]))) print(' ')

This way you loop over both loops and print the same index of both lists in the same loop.

The .format works as following:

print('text {} text {}'.format(<first thing>, <second thing>))

outputs:

text <first thing> text <second thing>

Andrew Zacharakis · Accepted Answer · 2018-03-17 15:55:48Z

The j in the first loop will not increase until 'i' traverse through every element, so j will print 1.20 both times. For traversing through both lists at the same time you can use one for loop.

for j in range(len(userlst)): print("Movies: " + str(movielst[j])) print("Users: " + str(userlst[j]))

The output will be :

Movies: A WALK,DRAGONBALL Users: [1, 20] Movies: JAMES BOND,MISSION Users: [6, 7]

Aaditya Ura · Accepted Answer · 2018-03-18 09:05:11Z

You can try this:

movielst = ['A WALK,DRAGONBALL', 'JAMES BOND,MISSION'] userlst = [[1,20],[6,7]] for i in zip(movielst,userlst): print("Movies : {}".format(i[0])) print("Users : {} {}".format(*i[1]))

output:

Movies : A WALK,DRAGONBALL Users : 1 20 Movies : JAMES BOND,MISSION Users : 6 7

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