If I have a
public void Method(int m) { ... } how can I create a thread to this method?
Thread t = new Thread((Method));
t.Start(m);
is not working.
- 1What exactly is happening? What isn't working? Are you getting an error message or is the method just not working? Can you post some additional code?Doug S.– Doug S.2011-03-01 14:44:46 +00:00Commented Mar 1, 2011 at 14:44
- yes I have an error: cannot convert from method group to System.Threading.ParameterizedThreadStartelisa– elisa2011-03-01 14:46:31 +00:00Commented Mar 1, 2011 at 14:46
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5 Answers
You can do this using a lambda expression. The C# compiler automatically creates the ThreadStart delegate behind the scenes.
Thread t = new Thread(() => Method(m)); t.Start(); Note that if you change m later in your code, the changes will propagate into the thread if it hasn't entered Method yet. If this is a problem, you should make a copy of m.
2 Comments
elisa
It works. Thx a lot. Justin I would like to ask you if I use t.Start it means that every time i want to call this method I will be able to run the code?
Justin
@elisa - No, you need to create a new thread for each call to
Start. Per the documentation of Thread.Start: "Once the thread terminates, it cannot be restarted with another call to Start."The method you are calling requires a parameter. Because it has one parameter and a return type of void you can use the following
ThreadPool.QueueUserWorkItem(o => Method(m)); You do not need to change the int to an object in the method signature using this method.
There are advantages to using the ThreadPool over starting your own Thread manually. Thread vs ThreadPool
6 Comments
elisa
I have the error: no overload for "Method"" matches delegate "System.Threading.WaitCallback". Please help
user
WaiCallback != WaitCallback. Double-check your spelling.
elisa
OK...sorry for mistake. But the error still persist. Any ideas for how to solve it?
Peter Kelly
@elisa You need to change the signature of the method to Method(object m) and then cast to an int in the body of the method.
Peter Kelly
@elisa Please try again - you do not need to change your method signature to an object with this one.
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ThreadStart tsd = new ThreadStart(ThreadMethod); Thread t = new Thread(tsd); t.Start(); Thread methods needs to be a method with return type void and accepting no argument.
public void ThreadMethod() {.....} There is another variant which is ParameterizedThreadStart
ParameterizedThreadStart ptsd = new ParameterizedThreadStart(ThreadParamMethod); Thread t = new Thread(ptsd); t.Start(yourIntegerValue); ThreadParamMethod is a method which return type is void and accept one argument of type object. However you can pass just about any thing as object.
public void ThreadParamMethod(object arg) {.....} 
1 Comment
Justin
Can't you shorten the
ParameterizedThreadStart example by getting rid of ptsd and just doing Thread t = new Thread(ThreadParamMethod);? Will the compiler automatically construct the ParameterizedThreadStart delegate? (I honestly haven't tried)Method needs to take an object not an int to be able to use the ParameterizedThreadStart delegate.
So change m to an object and cast it to an int first off.
Comments
please try:
Thread t = new Thread(new ThreadStart(method)); t.Start(); 
