How to set a default value for key in dict, when the key value is not found in the dict in python

Question

I am trying to scrape some results from ebay with python and I am running into an error :

condition = item['condition'][0]['conditionDisplayName'][0] >>> KeyError: 'condition'`

This is the code in question :

for item in (parseddoc["findItemsByKeywordsResponse"][0] ["searchResult"][0]["item"]): condition = item['condition'][0]['conditionDisplayName'][0] print(condition)

I am trying to figure out a way to stop it from getting the error and just default to a preset value( "N/A" for example ) and continue with the loop. What's the best way to achieve that? Thanks

A defaultdict would generate the "condition" key, not default to somthing other if not present — Patrick Artner
– Patrick Artner, Commented Oct 12, 2018 at 10:15
consider putting your condition = in a try block and if exception is thrown change value to "N/A" — Ninad Gaikwad
– Ninad Gaikwad, Commented Oct 12, 2018 at 10:16

jpp · Accepted Answer · 2018-10-12 10:24:29Z

Use a try / except clause to catch KeyError:

for item in parseddoc["findItemsByKeywordsResponse"][0]["searchResult"][0]["item"]: try: condition = item['condition'][0]['conditionDisplayName'][0] except KeyError: condition = 'N/A' print(condition)

BioGeek · Accepted Answer · 2018-10-12 10:16:41Z

Add the following if/else statement to your loop:

for item in (parseddoc["findItemsByKeywordsResponse"][0]["searchResult"][0]["item"]): if 'condition' not in item: condition = 'N/A' else: condition = item['condition'][0]['conditionDisplayName'][0] print(condition)

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