Java - Catch Exception e

Question

What does the e mean in the following code?

try { // Do something } catch (Exception e) { // Do something }

I've been researching and have gotten nothing.

System.out.println("Thanks!");

e is a reference to the instance of the Exception, like s would be a reference to an instance of String when you declare like String s = "...";. Otherwise you won't be able to reference the exception and learn what's wrong with your code — MadProgrammer
– MadProgrammer, Commented Nov 12, 2018 at 22:55
@MadProgrammer so it doesn't have to be e? Could it be written as some other letter and still work? — Domani Tomlindo
– Domani Tomlindo, Commented Nov 12, 2018 at 22:56
The Exceptions lesson might provide you with better/more information — MadProgrammer
– MadProgrammer, Commented Nov 12, 2018 at 22:56
No, it doesn't have to be e. I often use exp, but it's kind of a personal thing. It's just the variable name — MadProgrammer
– MadProgrammer, Commented Nov 12, 2018 at 22:57

Elliott Frisch · Accepted Answer · 2018-11-12 22:56:20Z

It's a variable name. Exception is the type. e is the name. You can use a different name. You might display a message to the user (or a stack trace).

try { // Do something } catch (Exception ohNo) { System.out.printf("Caught exception %s doing something.%n", ohNo.toString()); ohNo.printStackTrace(); }

can you please check my question? i think you can help me on exception handling. thank you stackoverflow.com/questions/69747085/java-try-catch-exception

Jose Ortega · Accepted Answer · 2018-11-12 23:07:40Z

It is a object which contain info about an error happend. Inherit from throwable and give you a clear message of why your code went wrong

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