For example:
mytuple = ("Hello","World") def printstuff(one,two,three): print one,two,three printstuff(mytuple," How are you") This naturally crashes out with a TypeError because I'm only giving it two arguments when it expects three.
Is there a simple way of effectively 'splitting' a tuple in a tider way than expanding everything? Like:
printstuff(mytuple[0],mytuple[1]," How are you") Kinda,... you can do this:
>>> def fun(a, b, c): ... print(a, b, c) ... >>> fun(*(1, 2), 3) File "<stdin>", line 1 SyntaxError: only named arguments may follow *expression >>> fun(*(1, 2), c=3) 1 2 3 As you can see, you can do what you want pretty much as long as you qualify any argument coming after it with its name.
Not without changing the argument ordering or switching to named parameters.
Here's the named parameters alternative.
printstuff( *mytuple, three=" How are you" ) Here's the switch-the-order alternative.
def printstuff( three, one, two ): print one, two, three printstuff( " How are you", *mytuple ) Which may be pretty terrible.
Try the following:
printstuff(*(mytuple[0:2]+(" how are you",))) 
mytuple = ("Hello","World") def targs(tuple, *args): return tuple + args def printstuff(one,two,three): print one,two,three printstuff(*targs(mytuple, " How are you")) Hello World How are you You could try:
def printstuff(*args): print args Another option is to use the new namedtuple collections type.
args would be (("hello","world)," how are you") as tuple and string.Actually, it is possible to do it without changing the order of the arguments. First you have to transform your string to a tuple, add it to your tuple mytuple and then pass your larger tuple as argument.
printstuff(*(mytuple+(" How are you",))) # With your example, it returns: "Hello World How are you" 