Check if a JavaScript string includes a substring that matches a regex.
I have tried string.includes(substring)
var myString = "This is my test string: AA.12.B.12 with some other chars"; myString.includes(/^[A-Z]{2}\.\d{2}\.\[A-Z]{1}\.\d{2,3}$/); True, False
However, code doesn't compile
You can use .test() on your regular expression to check whether the pattern matches part of the string. As the pattern will need to match only a portion of the string, you will need to remove the ^ and $ characters as your matched pattern can be contained within a line. Also, there is no need to escape the character class bracket as you have tried to do so in your expression (\[), as you want the [ to be treated as a character class, not a literal square bracket:
const myString = "This is my test string: AA.12.B.12 with some other chars"; const res = /[A-Z]{2}\.\d{2}\.[A-Z]{1}\.\d{2,3}/.test(myString); console.log(res);If we look at the docs for String.prototype.includes() we can see it takes a string, not a regular expression. Instead, try RegExp.prototype.test().
Also, since you only want to match a sub-string, you'll need to remove the start and end anchors ^ and $. (More on regex anchors)
Your code becomes:
var myString = "This is my test string: AA.12.B.12 with some other chars"; var myRegex = /[A-Z]{2}\.\d{2}\.\[A-Z]{1}\.\d{2,3}/; console.log(myRegex.test(myString));
.test()with the string as the argument.