Time of the current day in seconds in Python

Question

I know how to get time of the current day in seconds

import time seconds=time.time() % 86400

However the result is valid for UTC. Is there elegant way to do that for local time? I am aware I could get that somehow from local time struct_time, but it will be rather complicated procedure. Is there any elegant way to do that?

Add the timezone offset to time.time() before getting the modulus. — Barmar
– Barmar, Commented Sep 19, 2019 at 16:55
Perhaps you could look at this answer: stackoverflow.com/a/15971505/8935887 — Brian Ton
– Brian Ton, Commented Sep 19, 2019 at 16:55
Can you post some example so that the answer is specific to the problem statement. — abheet22
– abheet22, Commented Sep 19, 2019 at 16:55
@Barmar The problem is that offset is changing due to summer saving time. — Pygmalion
– Pygmalion, Commented Sep 19, 2019 at 16:56

Barmar · Accepted Answer · 2019-09-19 17:06:12Z

1

It's not complicated to get it from struct_time.

t = time.localtime() secs = 3600 * t.tm_hour + 60 * t.tm_min + t.tm_sec

answered Sep 19, 2019 at 17:06

Barmar

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4 Comments

Pygmalion Over a year ago

I guess this is less complicated than stackoverflow.com/questions/19289016/…

Pygmalion Over a year ago

I expected there should be something simpler and seconds are rounded to integer.

Barmar Over a year ago

If you want the fraction you can add math.modf(time.time())[0]

Pygmalion Over a year ago

Or perhaps add time.time() % 1?

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