I have a bytes type data like this:
b"6D4B8BD5" the data is from a chinese character using unicode-escape code. it can be generate like this:
'测试'.encode('unicode-escape') result:
b'\\u6d4b\\u8bd5' how can I convert b"6D4B8BD5" to b'\u6d4b\u8bd5' or how can I convert b"6D4B8BD5" to '测试'?
unhexlify is a function to get the bytes, then decode with the right encoding:
>>> from binascii import unhexlify >>> s = b'6D4B8BD5' >>> unhexlify(s).decode('utf-16be') '测试' 
>>> str = b"6D4B8BD5" >>> chr(int(str[0:4], 16)) '测' >>> chr(int(str[4:8], 16)) '试' The working solution which returns the correct result and works for any string :)
Python 3.x
def convert(chars): if isinstance(chars, bytes): chars = chars.decode('ascii') chars = [''.join(c) for c in zip(chars[::4], chars[1::4], chars[2::4], chars[3::4])] return "".join([chr(int(c, 16)) for c in chars]) print(convert(b"6D4B8BD5")) +++++++ #> python test123.py 测试 def convert(chars): if isinstance(chars, bytes): chars = chars.decode('ascii') result = '' for i in range(len(chars) // 4): result += chr(int(chars[4 * i:4 * (i + 1)], 16)) return result print(convert(b"6D4B8BD5")) ++++++++ #> python test123.py 测试 
