Java SHA-256 Program provides wrong Hash

Question

I was solving challenges on Hackerrank.com and I met with this challenge about the java SHA-256 Cryptographic hash functions. here

I wrote the following piece of code as a solution. But some test cases are failing for my solution. Hoping to know what's wrong with my code.

public class Solution { public static String toHexString(byte[] hash) { BigInteger number = new BigInteger(1, hash); StringBuilder hexString = new StringBuilder(number.toString(16)); while (hexString.length() < 32) { hexString.insert(0, '0'); } return hexString.toString(); } public static void main(String[] args) { Scanner sc = new Scanner(System.in); String input = sc.next(); try { MessageDigest md = MessageDigest.getInstance("SHA-256"); System.out.println(toHexString(md.digest(input.getBytes(StandardCharsets.UTF_8)))); } // For specifying wrong message digest algorithms catch (NoSuchAlgorithmException e) { throw new RuntimeException(e); } } }

This is one test case that is failing.

Would be helpful to see what the expected answer/result should be … — tquadrat
– tquadrat, Commented Mar 18, 2020 at 7:12
In the picture, you can see the expected output of the program — Avishka Dambawinna
– Avishka Dambawinna, Commented Mar 18, 2020 at 12:31

user207421 · Accepted Answer · 2020-05-02 05:46:10Z

A 32-byte hash means a string of 64 characters. Each byte contains 2 hex digits, so you need 2 characters per byte:

while (hexString.length() < 64) { hexString.insert(0, '0'); }

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