I want to make a series, e.g, 1/2 + 3/4 + 5/6 + 7/8 + 9/10 + 11/12 as a string using loops in php. write now i have written this code:
$output=''; for ($i=0; $i < 6; $i++) { $output=$output.($i+1+$i).'/'.($i+2+$i); if ($i==5) { break; } else { $output=$output.'+'; } } echo nl2br("\n4: $output"); output:
1/2 + 3/4 + 5/6 + 7/8 + 9/10 + 11/12 is there any other better approach to do that?
preg_replace('/(\d+) \+ (\d+)/', '$1/$2', implode(" + ", range(1, 12))); With minimum of code it is:
$output = []; for ($i = 0; $i < 6; $i++) { $output[] = (2 * $i + 1) . '/' . (2 * $i + 2); } echo implode(' + ', $output); Start loop from 1 and make step of 2 instead of one. Then put every sequence to array and finally implode it with +
$output = []; for ($i = 1; $i <= 12; $i += 2) { $output[] = $i . '/' . ($i + 1); } echo implode(' + ', $output); as a string using loops in php. --> display as a string...
Use for loop and modulus operator %. Display first key, a forward slash, then continue the iteration outside that conditional and display the next key, then display a plus sign.
Continue iteration until you evaluate if the value is at the end of the array. Two conditionals inside the loop.
I used a iterator defined as $i as using a foreach loop would start at zero and you would have to do some extra code to get the last value.
$myArray = array(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16); $stmt = NULL; for($i = 0; $i < count($myArray); $i++){ if($myArray[$i] % 2 ){ $stmt .= $myArray[$i]."/"; }else{ if($myArray[$i] !== end($myArray)){ $stmt .= $myArray[$i].' + '; }else{ $stmt .= $myArray[$i]; } } } OUTPUT:
