How to check if array contain a value

Question

I am trying to create if condition with explicitly defined array:

So "standard" is:

public static void main(String[] args) { int[] number = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}; if(contains(number, 2)){ System.out.println("Array contain number 2"); } } public static boolean contains(final int[] array, final int v) { boolean result = false; for(int i : array){ if(i == v){ result = true; break; } } return result; }

But how should I create something like this:

public static void main(String[] args) { if(contains({1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, 2)){ System.out.println("Array contain number 2"); } }

Because I am getting an error Array initializer is not allowed here

if(contains(new int[] {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, 2)){ — Eran
– Eran, Commented Jul 16, 2020 at 8:09
You could change the signature of contains to this: contains(int v, int... array) then you can call it like this: contains(2, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10) — Lino
– Lino, Commented Jul 16, 2020 at 8:13

Vinay Hegde · Accepted Answer · 2020-07-16 09:53:29Z

Already people have answered in comment section, But here I am showing you how you can do it in Java8, if you are looking for some fancy way like this :

boolean result = Arrays.stream(array).anyMatch(x->x==2)

or By using IntStream.

boolean result = IntStream.of(array).anyMatch(x -> x == 2)

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