How to submit a form in Zend?

Question

I have following action to display a form

public function showformAction() { $this->view->form = new Form_MyForm(); $this->view->form->setAction( 'submitform' ); }

above action shows a form successfully with only one textarea and submit button.

And I am using following action to submit above form:

public function submitformAction() { $form = new Form_MyForm(); $request = $this->getRequest(); if ( $request->isPost() ) { $values = $form->getValues(); print_r($values);die(); } else { echo 'Invalid Form'; } }

Above action is showing following output:

Array ( [myfield] => )

It means it is not posting values correctly and always shows empty array or I am not getting posted values correctly. How to post values to submitformAction().

Thanks

VAShhh · Accepted Answer · 2011-06-11 12:10:28Z

I think you must use the isValid() before accessing the values of a submitted form, because it's right there that the values are checked and valorized

public function submitformAction() { $form = new Form_MyForm(); $request = $this->getRequest(); if ( $request->isPost() ) { if ($form->isValid( $request->getPost() )) { $values = $form->getValues(); print_r($values);die(); } } else { echo 'Invalid Form'; } }

Yes you are right. But use $request->getPost() instead of $_POST where you are checking isValid(); Thanks

regilero · Accepted Answer · 2011-06-11 12:10:05Z

In complement to @VAShhh response. With some more details: You need to do two things, populate your form fields with the POSTed data and applying security filters and validators to that data. Zend_Form provides one simple function which perform both, it's isValid($data).

So you should:

build your form
test you are in a POST request
populate & filter & validate this data
either handle the fact in can be invalid and re-show the form wich is now decorated with Errors OR retrieve valid data from the form

So you should get:

function submitformAction() { $form = new Form_MyForm(); $request = $this->getRequest(); if ( $request->isPost() ) { if (!$form->isValid($request->getPost())) { $this->view->form = $form; // here maybe you could connect to the same view script as your first action // another solution is to use only one action for showform & submitform actions // and detect the fact it's not a post to do the showform part } else { // values are secure if filters are on each form element // and they are valid if all validators are set $securizedvalues = $form->getValues(); // temporary debug print_r($securizedvalues);die(); // here the nice thing to do at the end, after the job is quite // certainly a REDIRECT with a code 303 (Redirect after POSt) $redirector = $this->_helper->getHelper('Redirector'); $redirector->setCode(303) ->setExit(true) ->setGotoSimple('newaction','acontroller','amodule'); $redirector->redirectAndExit(); } else { throw new Zend_Exception('Invalid Method'); } }

And as said in the code re-showing the form you shoudl really try to use the same function for both showing and handling POST as a lot of steps are really the same:

building the form
showing it in the view in case of errors

By detecting the request is a POST you can detect you are in the POST handling case.

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