how to generate strings with random lengths

Question

function generate(n) { const notations = [" U", " D", " R", " L", " F", " B"]; const switches = ["", "\'", "2"]; let last = null; let scrambles = ""; for (let i = 0; i < n; ++i) { //subtract 1 when you can't select the same as the last let available_notations = notations.length - (last === null ? 0 : 1); //one random for all combinations let random = Math.floor(Math.random() * available_notations * switches.length); let nt = Math.floor(random / switches.length); //notation value let sw = Math.floor(random % switches.length); //switch value if (last !== null && last <= nt) nt += 1; //add 1 when value bigger than last last = nt; scrambles += notations[nt] + switches[sw]; } return scrambles; }

so i have this code which will generate random strings like thisB U F' D' F2 L2 R F2 L2 B F' D2 U2 L' D' R' L2 F D R but they all generate with the same length which is whatever i put as n on the for loop

but i want the length to vary from a specfic number until a specfic number like for example i want it to generate with length of 20 until 25

Instead of passing n to the function, you can pass a min (e.g. 20) and a max (e.g. 25) to generate a random n. You can see how on MDN — secan
– secan, Commented Apr 22, 2021 at 8:35

Carsten Løvbo Andersen · Accepted Answer · 2021-04-22 08:32:15Z

You could try something like this:

I've added an option to add min and max number, with a default value.

function generate(nMin = 20, nMax = 25)

And then we use the line below to get a random number between min and max

var n = Math.floor(Math.random() * (nMax - nMin + 1) + nMin)

Demo

function generate(nMin = 20, nMax = 25) { const notations = [" U", " D", " R", " L", " F", " B"]; const switches = ["", "\'", "2"]; let last = null; let scrambles = ""; var n = Math.floor(Math.random() * (nMax - nMin + 1) + nMin) for (let i = 0; i < n; ++i) { //subtract 1 when you can't select the same as the last let available_notations = notations.length - (last === null ? 0 : 1); //one random for all combinations let random = Math.floor(Math.random() * available_notations * switches.length); let nt = Math.floor(random / switches.length); //notation value let sw = Math.floor(random % switches.length); //switch value if (last !== null && last <= nt) nt += 1; //add 1 when value bigger than last last = nt; scrambles += notations[nt] + switches[sw]; } return scrambles; } document.getElementById("div").innerHTML = generate(20, 25) + '<br/>' + generate(2);

<div id="div"></div>

hi thanks for answering, if i only call the function like this generate() without any values it will default to 20 and 25 right?

Sivakumar A · Accepted Answer · 2021-04-22 08:35:47Z

You can also try like this

function getRandomInt(min, max) { min = Math.ceil(min); max = Math.floor(max); return Math.floor(Math.random() * (max - min + 1)) + min; }

and then call your generator method like

var value = generate(getRandomInt(10, 25));

Here, 10 is the minimum and 25 is the maximum in range. It will produce various combinations on each execution.

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