How to run servlet on tomcat server

Question

I have create following java file,compile it and got .class file.

import java.io.*; import javax.servlet.*; import javax.servlet.http.*; public class HelloWorld extends HttpServlet { public void doGet(HttpServletRequest request, HttpServletResponse response) throws IOException, ServletException { response.setContentType("text/html"); PrintWriter out = response.getWriter(); out.println("<html>"); out.println("<body>"); out.println("<head>"); out.println("<title>First Example</title>"); out.println("</head>"); out.println("<body>"); out.println("<h1>Hello World!</h1>"); out.println("</body>"); out.println("</html>"); } }

Now i created directory abc/WEB-INF/classes under apache-tomcat-6.0.32/webapps directory so my classFile Path is : apache-tomcat-6.0.32/webapps/abc/WEB-INF/classes/HelloWorld.class and trying to access http://localhost:8080/abc/WEB-INF/classes/HelloWorld, but getting error "The requested resource (/abc/HelloWorld) is not available"

Where i am going wrong? or should i have to specify other configuration?

pdf.coreservlets.com Try giving this book a read. You wont be able to access anything inside your WEB-INF directly. — Sean
– Sean, Commented Aug 4, 2011 at 12:07

kiswa · Accepted Answer · 2014-06-17 12:37:07Z

you must define your servlet in the web.xml

<servlet> <servlet-name>HelloWorld</servlet-name> <servlet-class>yourpackage.HelloWorld</servlet-class> </servlet>

and then define the mapping from URL to servlet

<servlet-mapping> <servlet-name>HelloWorld</servlet-name> <url-pattern>/HelloWorld</url-pattern> </servlet-mapping>

and finally type the URL as: http://localhost:8080/abc/HelloWorld

fyr · Accepted Answer · 2011-08-04 07:22:29Z

2

You need to configure your servlet in your web.xml.

answered Aug 4, 2011 at 7:22

fyr

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