Overloading with rvalue references

Question

Perfect forwarding is great and all. But what do I do if I want to not perfectly forward and instead just overload, on something that happens to be a templated type?

template<typename T> void foo(T&& ref); template<typename T> void foo(const T& ref);

Won't work because the first overload will invoke perfect forwarding. I'd really like behaviour very similar to if the first was a normal lvalue reference- where T will always be a value type.

Howard Hinnant · Accepted Answer · 2011-08-16 15:35:59Z

3

#include <type_traits> template<typename T> typename std::enable_if < !std::is_reference<T>::value, void >::type foo(T&& ref) {} template<typename T> void foo(const T& ref) {}

answered Aug 16, 2011 at 15:35

Howard Hinnant

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2 Comments

Puppy Over a year ago

I never think of the SFINAE solution, because MSVC's support sucks. Thanks :)

Howard Hinnant Over a year ago

I don't know if support is better if you move the enable_if from the return type to the argument list?

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