Spring JPA how to create an object with relationship to another entity in Application

Question

I want to create a Person with an Address, each of them are an entity. My Entities seem to work, the part where i begin to struggle is on how to create a Person using the constructor where i also have to put in the Address.

personRepository.save(new Person(new Name("Test","Test"),new Adress("Street","Number","PLZ","Town"),LocalDate.parse("2000-01-01"),"[email protected]","911");

This sadly does not work so my question is how can i create a Person object with the Address.

I'm also wondering how i would add the address if i already got the address in my Address repository, is there a way to get the address or use the adress ID?

adresseRepository.save(new Adresse("Street","Number","PLZ","Town"));

Here's the code for both of the shortend.

Person:

@Entity @Table(name = "Person") public class Person { @Id @GeneratedValue(strategy = GenerationType.AUTO) @Column(name = "PersonID") private Long personID; @Column(name = "FullName") @Convert(converter = NameConverter.class) private Name fullName; @OneToOne(cascade = CascadeType.ALL) @JoinColumn(name="AdresseID") private Adresse adresse; @Column(name = "Geburtsdatum") private LocalDate geburtsdatum; @Column(name = "EMail") private String email; @Column(name = "Telefonnummer") private String telefonnummer; private Person() {} public Person(Name fullName, Adresse adresse, LocalDate geburtsdatum, String email, String telefonnummer) { this.fullName = fullName; this.adresse = adresse; this.geburtsdatum = geburtsdatum; this.email = email; this.telefonnummer = telefonnummer; } }

Address:

@Entity @Table(name = "Adresse") public class Adresse { @Id @GeneratedValue(strategy = GenerationType.AUTO) @Column(name = "AdresseID") private Long adresseID; @Column(name = "Strasse") private String strasse; @Column(name = "Hausnummer") private String hausnummer; @Column(name = "PLZ") private String plz; @Column(name = "Ort") private String ort; protected Adresse() {} public Adresse(String strasse, String hausnummer, String plz, String ort) { this.strasse = strasse; this.hausnummer = hausnummer; this.plz = plz; this.ort = ort; } }

Christoph Kronberger · Accepted Answer · 2022-06-10 05:51:57Z

Ralationships are created in hibernate like this:

@Entity @Table(name="CART") public class Cart { //... @OneToMany(mappedBy="cart") private Set<Item> items; // getters and setters }

Please note that the @OneToMany annotation is used to define the property in Item class that will be used to map the mappedBy variable. That is why we have a property named “cart” in the Item class:

@Entity @Table(name="ITEMS") public class Item { //... @ManyToOne @JoinColumn(name="cart_id", nullable=false) private Cart cart; public Item() {} // getters and setters }

Soin your case you just have to add

@Entity @Table(name = "address") public class Address { @Id @GeneratedValue(strategy = GenerationType.AUTO) @Column(name = "id") private Long id; //... @OneToOne(mappedBy = "address") private User user;

something lilke this to your Adress Table. Because one Adress also have one user.

For more information visit this site

Thanks it added this to my source code. But i still got the issue that if i use the same adress for two users the adress gets added twice instead of just having it once in the database

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