1

I am creating a Test Automation 'Health Page'

On this page I would like to display a 7 day trend of how many tests ended with status PASS/FAIL/UNDEFINED. I am doing it in Oracle Application Express. I would like the graph to look something like this: enter image description here

However I do not know how to separate the results into days. Here is my count query:

select sum (case when STATES.NAME='Pass'then 1 else 0 end) AS PASS, sum (case when STATES.NAME='Fail'then 1 else 0 end) AS FAIL, sum (case when STATES.NAME='Undefined'then 1 else 0 end) AS Undefined from TEST_CASE TEST INNER JOIN TEST_CASE_TEST_RUN TESTRUNCASE on TEST.TEST_CASE_ID=TESTRUNCASE.TEST_CASE_ID INNER JOIN TEST_RUN RUN on TESTRUNCASE.TEST_RUN_ID=RUN.TEST_RUN_ID INNER JOIN EXECUTION EXE on TESTRUNCASE.TEST_CASE_IN_TEST_RUN_ID=EXE.TEST_CASE_IN_TEST_RUN_ID LEFT JOIN TEST_STEP_STATE STATES on STATES.TEST_STEP_RESULT_STATE_ID=EXE.TEST_STEP_RESULT_STATE_ID where actual_Start_date > sysdate -7 ; 

This is the result of the query:

enter image description here

How can I change the query to give me a result for DAY 1, DAY 2, DAY3 etc(Im ok if it also shows shortened version of date in format 'DD-MM')?

to_char(EXE.ACTUAL_END_DATE,'DD-MM') as DAY ,

1

1 Answer 1

1

You can use GROUP BY and to_char(actual_Start_date ,'d')which would return 1 - 7

select to_char(actual_Start_date ,'d') as days, sum (case when STATES.NAME='Pass'then 1 else 0 end) AS PASS, sum (case when STATES.NAME='Fail'then 1 else 0 end) AS FAIL, sum (case when STATES.NAME='Undefined'then 1 else 0 end) AS Undefined from TEST_CASE TEST INNER JOIN TEST_CASE_TEST_RUN TESTRUNCASE on TEST.TEST_CASE_ID=TESTRUNCASE.TEST_CASE_ID INNER JOIN TEST_RUN RUN on TESTRUNCASE.TEST_RUN_ID=RUN.TEST_RUN_ID INNER JOIN EXECUTION EXE on TESTRUNCASE.TEST_CASE_IN_TEST_RUN_ID=EXE.TEST_CASE_IN_TEST_RUN_ID LEFT JOIN TEST_STEP_STATE STATES on STATES.TEST_STEP_RESULT_STATE_ID=EXE.TEST_STEP_RESULT_STATE_ID where actual_Start_date > sysdate -7 GROUP BY 1; 
Sign up to request clarification or add additional context in comments.

Comments

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.