How to send a link to an image in a response

Question

I want to send a link to a photo in the response, which is on the hosting, I'm running a django application on the hosting via python manage.py runserver 0.0.0.0:8000 . How do I make it so that in the response to the request there is a link to the image that is on the hosting.

Example: I get this response when accessing the API

{ "title": "add", "description": "some text", "image": "http://127.0.0.1:8000/media/photo_2022-09-12_20-57-08.jpg", "created_at": "2022-09-12T22:24:42.449098+03:00" }

I want to get this answer:

{ "title": "add", "description": "some text", "image": "domain.api/media/photo_2022-09-12_20-57-08.jpg", "created_at": "2022-09-12T22:24:42.449098+03:00" } models.py class Event(models.Model): title = models.TextField() description = models.TextField() image = models.ImageField(blank=True) is_main = models.BooleanField(default=False) created_at = models.DateTimeField(auto_now_add=True) def __str__(self): return self.title views.py class EventDetailOrList(viewsets.ReadOnlyModelViewSet): queryset = Event.objects.all() serializer_class = EventSerializer filter_backends = (filters.DjangoFilterBackend,) filterset_class = EventFilter

Please go through docs.djangoproject.com/en/4.1/ref/contrib/sites/…. This way you first have to set up your site then by default your media files will be served through your site domain. — Deepak Tripathi
– Deepak Tripathi, Commented Sep 15, 2022 at 19:58

Ahmet Deger · Accepted Answer · 2022-09-15 23:06:36Z

Let's do it step by step:

1. settings.py

INSTALLED_APPS = [ ... ... ... 'django.contrib.sites', ... ... ] SITE_ID = 1

after that, you need to run migrate

python manage.py migrate

2. models.py

class Event(models.Model): title = models.TextField() description = models.TextField() image = models.ImageField(blank=True) is_main = models.BooleanField(default=False) created_at = models.DateTimeField(auto_now_add=True) def get_image(self): if self.image: return Site.objects.get_current().domain + self.image.url else: return ""

3. serializers.py

class EventSerializer(serializers.ModelSerializer): class Meta: model = Event fields = [ 'title', 'description', 'get_image', 'created_at', ]

after these steps, you can edit your site domain on the Django Admin panel.

I hope this helps!

T. Lang · Accepted Answer · 2022-09-15 19:57:10Z

I would use the socket module to grab the hostname of the IP:

import socket address = 127.0.0.1:8000 host = socket.gethostbyaddr(address) return host

Nealium · Accepted Answer · 2022-09-15 20:04:05Z

If you have access to the request object you can do something like

request.META['REMOTE_ADDR'] # '127.0.0.1' root = request.META['HTTP_HOST'] # '127.0.0.1:8000' # combined with: from django.templatetags.static import static path = static('media/nealium_avatar.png') full = '{0}/{1}'.format(root, path) # full = '127.0.0.1:8000/static/media/nealium_avatar.png'

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