Can you do something like this?
struct Person { hp: i32 } struct EvolvedPerson { hp: i32, evolved_stat: i32, } let p1 = Person { hp: 10 } let p2 = EvolvedPerson { ..p1, extra_stat: 20 } Where the p2 now has the hp of p1.
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3 Answers
As a possible solution you can deconstruct p1 and then provide variables to p2 by shorter syntax:
struct Person { hp: i32 } struct EvolvedPerson { hp: i32, evolved_stat: i32, } let p1 = Person { hp: 10 }; let p2 = { let Person { hp } = p1; EvolvedPerson { hp, extra_stat: 20 } }; 
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The idiomatic way would be to include the Person struct instead:
struct Person { hp: i32, } struct EvolvedPerson { person: Person, evolved_stat: i32, } let p1 = Person { hp: 10 } let p2 = EvolvedPerson { person: p1, extra_stat: 20 } That way it is also trivial to implement AsRef<Person> for EvolvedPerson and thus you can use Person methods with EvolvedPerson too.
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Can you do something like this?
No. You can only unpack structs of the same type.
