Find minimum in array of dictionaries? [duplicate]

Question

I have something like :

var array = [ {'a':3,'b':4}, {'a':1,'b':8}, {'a':9,'b':7}]

What is an elegant one line to find the min/max of the key 'a' (max=9, min = 1) ? I know it is simple but i couldn't find a one line solution only loops.

So what is the result, precisely? 1 or 9 or { a: 9, b: 7 } or { a: 1, b: 8 } or { min: 1, max: 9 } or { min: { a: 1, b: 8 }, max: { a: 9, b: 7 } } or something else? Countless options, no example, no effort, no surprise it got downvoted. — Sebastian Simon
– Sebastian Simon, Commented Dec 21, 2022 at 8:54
I wish the new generation of JS coders stopped looking for inefficient one liners and focus on performance and readability.. Wait, did I just made an old man rant? — Kaddath
– Kaddath, Commented Dec 21, 2022 at 8:55
@gotiredofcoding Not my downvote, but people do tent to downvote questions that don't show any effort, as they come across like "do my work for me" questions. — Ivar
– Ivar, Commented Dec 21, 2022 at 8:55
Here's a useless solution that only traverses the array once to get both min and max: const [min, max] = array.reduce(([min, max], { a }) => [a < min ? a : min, a > max ? a : max], [Infinity, -Infinity]). — Hao Wu
– Hao Wu, Commented Dec 21, 2022 at 9:06
> calls us childish > engages in childish behavior in response to valid criticism about the nature of your question wut — Mike Warren
– Mike Warren, Commented Dec 21, 2022 at 9:13

Nitheesh · Accepted Answer · 2022-12-21 09:08:08Z

Logic

Create a simple array of the required nodes.
Use Math.max with the spread syntax to get the maximum.

const array = [{ a: 3, b: 4 },{ a: 1, b: 8 },{ a: 9, b: 7 }]; const max = Math.max(...array.map(({ a }) => a)); console.log(max);

Apply the same logic for min as well and use Math.min

const array = [{ a: 3, b: 4 },{ a: 1, b: 8 },{ a: 9, b: 7 }]; const nodes = array.map(({ a }) => a); const maxMin = { max: Math.max(...nodes), min: Math.min(...nodes)}; console.log(maxMin);

Nitheesh · Accepted Answer · 2022-12-21 09:07:26Z

1

you can do something like this

var array = [ { a: 3, b: 4 }, { a: 1, b: 8 }, { a: 9, b: 7 }, ]; const arrayA = array.map((v) => v.a); const maxA = Math.max(...arrayA); const minA = Math.min(...arrayA); console.log({ minA, maxA });

edited Dec 21, 2022 at 9:07

Nitheesh

20.1k3 gold badges28 silver badges52 bronze badges

answered Dec 21, 2022 at 8:55

R4ncid

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2 Comments

Hao Wu Over a year ago

Technically it's not a one-liner, though.

Andy Over a year ago

"do something like this" without explanatory commentary isn't particularly useful.

Nitheesh · Accepted Answer · 2022-12-21 09:06:47Z

Tried to keep it in 1 line.

var array = [ { a: 3, b: 4 }, { a: 1, b: 8 }, { a: 9, b: 7 }, ]; const result = { min: Math.min(...array.map((x) => x.a)), max: Math.max(...array.map((x) => x.a)), }; console.log(result);

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