Why my code showing error: unreported exception IOException; must be caught or declared to be thrown at bw.write(s); [duplicate]

Question

Problem Statement: Given an array of integers, answer queries of the form: [i, j] : Print the sum of array elements from A[i] to A[j], both inclusive

This is the code I used:

import java.io.*; import java.util.*; public class Solution { public static void main(String[] args) { /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */ Scanner sc=new Scanner(System.in); BufferedWriter bw=new BufferedWriter(new OutputStreamWriter(System.out)); int n=sc.nextInt(); long arr[]=new long[n]; for(int i=0;i<n;i++) arr[i]=sc.nextLong(); long farr[]=new long[n]; farr[0]=arr[0]; for(int i=1;i<n;i++) farr[i]=farr[i-1]+arr[i]; int q=sc.nextInt(); while(q-->0){ int i=sc.nextInt(); int j=sc.nextInt(); if(i!=0){ //I'm converting long value to String bcoz bw can't write long value in buffer String s=String.valueOf(farr[j]-farr[i-1]); bw.write(s); } else{ String s=String.valueOf(farr[j]); bw.write(s); } } bw.flush(); bw.close(); } }

I tried the above code for Sum of Subarray problem

Exceptions are thrown. This is a compiler error, not an exception, and it is displayed, or printed, or shown. Not 'thrown'. — user207421
– user207421, Commented May 8, 2023 at 6:10

Smanika · Accepted Answer · 2023-03-28 06:36:20Z

You need to add an exception to the method signature.

public static void main(String[] args) throws IOException

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Why my code showing error: unreported exception IOException; must be caught or declared to be thrown at bw.write(s); [duplicate]

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