(TS 2556) Why am I recieving a type error on a spread argument that has already been explicitly typed and passed as a rest parameter?

Question

function debouncePromise<TParams extends Array<unknown>, TRes>( fn: (a: TParams) => Promise<TRes>, time: number, ) { let timerId: ReturnType<typeof setTimeout> | undefined = undefined; return function debounced(...args: TParams) { if (timerId) { clearTimeout(timerId); } return new Promise((resolve) => { timerId = setTimeout(() => resolve(fn(...args)), time); //<= A spread argument must either have a tuple type or be passed to a rest parameter.ts(2556) }); }; }

I have already typed the spread argument in the function as a rest parameter. Why am I recieving an error on an argument/variable that has already been explicitly typed? How do I resolve this?

Update: tsplayground

Do you have a minimal reproducible example for this? (e.g. on the typescript playground or the like? And if you do, don't replace your code, just add the link to that in your post). But in the absence of that: fn was declared as taking 1 argument, of type TParams, on line 2. But on line 12 you're not passing it 1 argument of type TParams. — Mike 'Pomax' Kamermans
– Mike 'Pomax' Kamermans, Commented Mar 21, 2024 at 0:50
@Mike'Pomax'Kamermans ahhh i changed it to fn: (...a: TParams) => and that resolved it! thank you :) — tem
– tem, Commented Mar 21, 2024 at 1:02

tem · Accepted Answer · 2024-03-21 01:06:34Z

0

Made a change in line 2 to fn: (...a: TParams) => and that resolved it!

answered Mar 21, 2024 at 1:06

tem

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(TS 2556) Why am I recieving a type error on a spread argument that has already been explicitly typed and passed as a rest parameter?

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