Compare button text

Question

Ok my pattience is gone now...I tried for 30 minutes to make this simple thing work but I failed so bad.Maybe it is because I started directly with android,no java...I studied c++ before,and in c++ this was so easy to do...

I have a button in a xml file:

 <Button android:text="Button" android:layout_width="wrap_content" android:id="@+id/button1" android:layout_height="wrap_content" android:layout_alignParentBottom="true" android:layout_alignParentLeft="true" android:layout_marginBottom="108dp"> </Button>

And in my java file I have a string like this:

 String test = new String(); test = "google";

I 've already set up the onclick listener for the button so there is no problem. My question is if:

 Button buttonx = (Button)findViewById(R.id.button1);

How can I compare if onClick(onclick code is already made) buttonx's text = the string test that is "google".

I tried with getText,setText...but nothing...

Cameron Skinner · Accepted Answer · 2011-10-30 07:00:33Z

OK. First things first: Strings are completely different in Java to C++. In fact, Objects are pretty different all-round.

String test = new String(); test = "google";

does not do what you think it does.

What this does is create a new empty String object and store a reference to it in test. The next line stores a reference to a constant String "google" in test and makes the empty String you constructed in the previous line eligible for garbage collection. This is completely different to C++, where the second line would actually call the = operator on the String class. You can kinda think of everything in Java being a pointer (but not really), so assignment in Java behaves like pointer assignment in C++ (but not really).

Back to your question.

Something like this might work:

String test = "google"; Button b = ...; if (test.equals(b.getText()) { // whatever }

Remember that although Java and C++ share some syntax similarities they are really completely different languages. Java references kinda behave like pointers, but not really.

Really.

goto10 · Accepted Answer · 2011-10-30 06:59:07Z

String test = new String(); test = "google"; Button buttonx = (Button)findViewById(R.id.button1); if (test.equals(buttonx.getText())) { // it's equal }

bos · Accepted Answer · 2011-10-30 06:59:07Z

if (button.getText().toString().equalsIgnoreCase(test)) Toast.makeText(this, "Button text equals!", Toast.LENGTH_SHORT).show(); else Toast.makeText(this, "Button text is not the same.", Toast.LENGTH_SHORT).show();

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