The following snippet samples elements with replacement from a vector:
use rand::seq::IteratorRandom; fn main() { let mut rng = rand::rng(); let values = vec![1, 2, 3, 4, 5] as Vec<i32>; let mut samples = Vec::new(); for _ in 1..10 { let v = values.iter().choose(&mut rng).unwrap(); samples.push(v); } println!("{:?}", samples); } Is there a more idiomatic/Rustic way of achieving the same thing?
Related: How to create a random sample from a vector of elements?
This uses IndexRandom to sample from a Vec (or anything that derefs into a slice).
use rand::seq::IndexedRandom; fn main() { let mut rng = rand::rng(); let values = vec![1_i32, 2, 3, 4, 5]; let samples = (0..10) .map(|_| values.choose(&mut rng).unwrap()) .collect::<Vec<_>>(); println!("{:?}", samples); // [2, 4, 5, 1, 2, 2, 2, 3, 4, 2] } My own answer which produces the same effect is:
use rand::seq::IteratorRandom; fn main() { let mut rng = rand::rng(); let values = vec![1, 2, 3, 4, 5] as Vec<i32>; let samples: Vec<_> = (1..10).map(|_| *values.iter().choose(&mut rng).unwrap()).collect(); println!("{:?}", samples); } Remark: I am not however sure how to fix the seed to have exactly reproducible results.