why (void) is used while invoking function? [duplicate]

Question

Possible Duplicate:
casting unused return values to void
Need for prefixing a function with (void)
Casting function returns to void

Have seen in quite few places that while invoking the function why do we explicitly the return type of the function ? ex:

(void) myhostnames ( char * something);

What is use of this (void), and how it differs from not using the same ? Kindly clarify.

Similar question stackoverflow.com/questions/689677/…

int
– int

2012-03-20 15:07:56 +00:00
Commented Mar 20, 2012 at 15:07 — int
– int, Commented Mar 20, 2012 at 15:07

cnicutar · Accepted Answer · 2012-03-20 15:07:16Z

4

Perhaps the function returns something and to prevent warnings from the compiler / errors from lint, the caller explicitly "throws" away the return.

answered Mar 20, 2012 at 15:07

cnicutar

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1 Comment

David Schwartz Over a year ago

It's a way of the programmer saying to anyone who reviews this code (whether human or machine), "I know that this function returns a value and in this case the right thing to do is ignore that value. I'm calling this function for some reason other than to get its return value."

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