JavaFX 2.0 - create action handler for custom component in FXML

Question

I want to add a custom action in my new component. How to do this?

Example code:

Component

public class MyCustomComponent extends Region { public MyCustomComponent(){ super(); this.setOnMouseClicked(new EventHandler<MouseEvent>(){ @Override public void handle(MouseEvent event) { /* throw my custom event here and handle it in my FXML controller - but how? :-( */ } }); } }

Controller

public class MyController { @FXML protected void myCustomAction(ActionEvent event) { // do something } }

FXML:

<BorderPane fx:controller="fxmlexample.MyController" xmlns:fx="http://javafx.com/fxml"> <top> <MyCustomComponent onAction="#myCustomAction"> </MyCustomComponent> </top> </BorderPane>

Thx for help

Sergei Grinev · Accepted Answer · 2012-04-01 15:47:36Z

You need to implement property in your custom component, which will store your action.

public class MyCustomComponent extends Region { public MyCustomComponent(){ super(); // just to find out where to click setStyle("-fx-border-color:red;"); setPrefSize(100, 100); this.setOnMouseClicked(new EventHandler<MouseEvent>(){ @Override public void handle(MouseEvent event) { onActionProperty().get().handle(event); } }); } // notice we use MouseEvent here only because you call from onMouseEvent, you can substitute any type you need private ObjectProperty<EventHandler<MouseEvent>> propertyOnAction = new SimpleObjectProperty<EventHandler<MouseEvent>>(); public final ObjectProperty<EventHandler<MouseEvent>> onActionProperty() { return propertyOnAction; } public final void setOnAction(EventHandler<MouseEvent> handler) { propertyOnAction.set(handler); } public final EventHandler<MouseEvent> getOnAction() { return propertyOnAction.get(); } }

and don't forget to add import in your fxml file:

<?import my.package.MyCustomComponent?>

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