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Assuming Square wave of 100 Hz. I know it also contain all odd harmonics at different amplitude. I also Understand that if I will pass it via a LP filter with a cutoff frequency of 350Hz I will not hear the harmonics above 300Hz ( or they will reduce massively in amplitude) and therefore the output waveform will change from square like to more of a sin wave. I don't understand the relation between the waveform and his harmonic content to to the resulting sound. How can you explain it? I try to understand why when a square wave with sharp edges when shooting his edges it result in a waveform with less high harmonic content?

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This website https://www.geogebra.org/m/wUanseCs offers an interactive visualization of the building of a square wave from a sum of 'sin' functions. You can see the effect of a low pass filter by removing the higher frequencies components. Hope that it helps.

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  • $\begingroup$ Hi! I think this answer would be really good (and stand on its own, which we very much prefer answers to do, because external links go away with time), if you quickly explained why (I think you're already super close to doing that anyways: you'd need to spell out that "building of a square wave" means adding up harmonic signals, and if you low-pass filter these, you get only the harmonic signals below the filter's cutoff frequency). Do you think you could add that to your answer? $\endgroup$ Commented Jan 19 at 16:25
  • $\begingroup$ why fast frequency of the harmonic content are blocked while slower frequency pass? I mean in term of the charge nad discharge of the cap $\endgroup$ Commented Jan 19 at 16:33
  • $\begingroup$ Hi @user80760! That looks like either a substantive addition to your question, or a separate question altogether. In addition to liking complete answers, StackExchange likes complete questions, without game-changing content buried in comments. Please edit your question with this new query, or ask a new one. $\endgroup$ Commented Jan 19 at 21:32

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