1
\$\begingroup\$

I've just started writing a 3D First Person Shooter in Java, and I'm having a bit of trouble with tracking the mouse movements and moving the camera accordingly. I'm implementing typical FPS movement, in that the mouse stays at the center of the screen.

Moving the mouse left and right (horizontal movement) is fine - each time the mouse is moved, I get it's position on the screen. I then use atan2 to get the angle I need to rotate around the y axis to get to this position, and apply the rotation accordingly.

My problem is when I try to change the pitch of the view (i.e. rotating around the x axis - essentially looking up and down). I can get the y coordinate of the mouse, and the y coordinate of the center of the screen, but how do I calculate how much I need to rotate around the x axis to get to that point?

Thanks in advance!

\$\endgroup\$
4
  • \$\begingroup\$ uh.... what's the difference between the x and y axis? Can't you just do the same thing? \$\endgroup\$ Commented Mar 19, 2013 at 12:29
  • \$\begingroup\$ @Liosan I've tried that, and it's not working out for me. So to get the y rotation, I'm using double yRad = Math.atan2(mouseX, centerX);, so theoretically to get the x rotation, I should use double xRad = Math.atan2(mouseX, centerX), correct? This is giving me some very weird/erratic behaviour (and thus I thought I must have been doing something wrong). \$\endgroup\$ Commented Mar 19, 2013 at 12:48
  • \$\begingroup\$ I'm sure it's just a typo in your comment, but you're not using mouseY and centerY. \$\endgroup\$ Commented Mar 19, 2013 at 13:11
  • \$\begingroup\$ Yep, sorry about that - it's a typo.. Math.atan2(mouseY, centerY);* \$\endgroup\$ Commented Mar 19, 2013 at 13:13

3 Answers 3

Reset to default
1
\$\begingroup\$

I don't know why you think you should use Atan2, but you shouldn't. And I'm surprised that you get anything that looks useful that way.

double yRad = (mouseY-centerY)*sensitivityY; Where yRad is the amount to turn, and the mouse is centred after the reading is really all there is to it.

\$\endgroup\$
4
  • \$\begingroup\$ I've added this, and it works. However, the camera will only ever move in one direction, regardless of where I move the mouse. So if I move the mouse up or down, the camera always rotates in one direction. That was why I was using atan2. Sorry if these seem like stupid questions - I'm shocking at maths.. \$\endgroup\$ Commented Mar 20, 2013 at 2:05
  • \$\begingroup\$ @Kumalh What does the rest of your rotation code look like? \$\endgroup\$ Commented Mar 20, 2013 at 14:57
  • \$\begingroup\$ So after I determine the amount to rotate, I call this method for both the x and y: private void rotateY(double rad) { targetTG.getTransform(t3d); toRot.rotY(-rad); t3d.mul(toRot); targetTG.setTransform(t3d); } \$\endgroup\$ Commented Mar 23, 2013 at 3:45
  • \$\begingroup\$ @Kumalh That is your exact code? Assuming toRot is a transformation matrix, it is not reset, so it will accumulate whatever transformations has been applied to it. How are you allowed to call getTransform with a parameter, it should return the transformation. In any case, I'd strongly advise that you keep track of the pitch and yaw yourself, like yRadTotal += yRad, and then for each frame set the specific rotation using these two values. \$\endgroup\$ Commented Mar 23, 2013 at 8:54
1
\$\begingroup\$

Maybe your problem is not related to angle calculation, but the way you take your measurements.

Most FPS games use the following scheme:

  • Read mouse position on screen
  • Move mouse back to the center of the screen

This way, every frame you measure movement of the mouse, and not the position on screen. This allows for much more fluent and precise camera movement.

\$\endgroup\$
0
\$\begingroup\$

I'm not sure if I understand what you are trying to achieve. From my understanding, and from how I am doing it in my game, the usual thing is to calculate:

horizontalAngle += ( mousePositionOnScreenX - screenCenterX ) * sensitivityX; verticalAngle += ( mousePositionOnScreenY - screenCenterY ) * sensitivityY;

And then of course mouse is moved back to the centre.

\$\endgroup\$

You must log in to answer this question.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.