4
$\begingroup$

Let $A$ be an $8\times 8$ complex matrix with characteristic polynomial $$p_A(x)=(x-1)^4(x+2)^2(x^2+1)$$ and minimal polynomial $$m_A(x)=(x-1)^2(x+2)^2(x^2+1).$$ Determine all possible Jordan canonical forms of $A$. Also, what is the dimension of the eigenspace for $\lambda = 1$ for each case?

I haven't learned minimal polynomial yet, so I wanted to check if I am on the right track.

From the characteristic polynomial, the eigenvalues are $i,-i,-2,1$. From the minimal polynomial, the block sizes are $1,1,2$ for eigenvalues $i,-i,-2$ respectively. For $\lambda = 1$, the largest block size is 2, so the possible block sizes are $2,2$, which has eigenspace dim of 2 ($J_1$). Or the sizes are $2,1,1$, which has eigenspace dim of 3 ($J_2$). Writing the full Jordan matrix:

$J_1=\begin{pmatrix}1&1&0&0&0&0&0&0\\0&1&0&0&0&0&0&0\\0&0&1&1&0&0&0&0\\0&0&0&1&0&0&0&0\\0&0&0&0&-2&1&0&0\\0&0&0&0&0&-2&0&0\\0&0&0&0&0&0&i&0\\0&0&0&0&0&0&0&-i\end{pmatrix}$, $J_2=\begin{pmatrix}1&1&0&0&0&0&0&0\\0&1&0&0&0&0&0&0\\0&0&1&0&0&0&0&0\\0&0&0&1&0&0&0&0\\0&0&0&0&-2&1&0&0\\0&0&0&0&0&-2&0&0\\0&0&0&0&0&0&i&0\\0&0&0&0&0&0&0&-i\end{pmatrix}$

$\endgroup$
2
  • 2
    $\begingroup$ Looks to me like you did everything right! $\endgroup$ Commented Jul 19, 2016 at 2:37
  • $\begingroup$ @Christian yay! thank you $\endgroup$ Commented Jul 19, 2016 at 2:52

1 Answer 1

0
$\begingroup$

You identified the blocks and eigenspace dimensions correctly. The blocks for a given form, however, can be permuted. Thus, your first matrix represents 5!/2! = 60 forms, and your second matrix, 6!/2! = 360 forms for a total of 420 forms.

$\endgroup$

You must log in to answer this question.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.