0
$\begingroup$

I have a set of data points looking as if they could follow a skew-normal distribution when plotted. The explicit way the data is generated is unknown, but 2 things are constant for each set {$x,y$} these constant parameters are: $T=4$, $L=2\pi/26$. Additionally, we know the value of a 3rd parameter $A=a*T$ for each curved plotted. The data plots are bellow:

enter image description here

semi log plot of data

What type of function/fit can be used to reproduce this behaviour in terms of the parameters listed? I unsuccessfully tried $y(x)=1+a*e^{-(b*x+e^{-b*x})}$ the Gumbel distribution. The data for A=1..5 is here data.ods or csv here CSv format

$\endgroup$
2
  • $\begingroup$ Can you provide the data on another way than data.ods ? I cannot download the data without the required password. $\endgroup$ Commented Feb 28 at 11:08
  • $\begingroup$ @JJacquelin I put also a link to csv format should work with no passwords at all or try here filebin.net/dlzjdtfifcol5euo $\endgroup$ Commented Feb 28 at 13:26

1 Answer 1

1
$\begingroup$

In order to improve the fitting one can increase the number of adjustable parameters in the function. For example instead of $$y(x)=1+a\:\exp\left(-b\;x-e^{b\;x} \right)$$ which is equivalent to $$Y(x)=\ln\left(y-1\right)=\ln(a)-b\;x-e^{b\;x}$$ the next modified function gives much better result : $$y(x)=1+a\:\exp\left(-b\;x-c\;e^{p\;x}-d\;e^{q\;x }\right)$$ Or equivalently : $$Y(x)=\ln(y-1)=\ln(a)-b\;x-c\;e^{p\;x}-d\;e^{q\;x }$$ Result in case $A=1$ :

enter image description here

$\endgroup$

You must log in to answer this question.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.