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Questions tagged [multinomial-distribution]

Questions in probability which includes more than one random variable

3 votes
1 answer
120 views

I am considering the following probabilistic balls-into-bins model. There are $n$ bins and two types of balls. For each type, there are $\rho$ balls. Each ball independently lands in bin $i$ with ...
Idra's user avatar
  • 210
-1 votes
1 answer
157 views

From this question, i get that, given a random vector $ (X_1,...,X_m) \sim M(n;p_1,...,p_m)$, the expected value of the product of two variables is $E[X_1X_2] = n(n-1)p_1p_2$. It is possible to obtain ...
Lex's user avatar
  • 3
0 votes
0 answers
112 views

Context: I am trying to find $\text{Corr}(X,Y)$ where $X$ is a random variable with given $\text{Var}(X)=v$ and $\mathbb E(X)=e$. And $Y$ is a random variable with multinomial distribution $Y\sim\text{...
Iii's user avatar
  • 3
12 votes
2 answers
306 views

We are given a multinomial distribution with $k$ bins and $n$ balls. The number of balls is at most the number of bins, i.e., $\sqrt{k} \le n \le k$. The probabilities of throwing a ball into a ...
CuriousGuy's user avatar
6 votes
4 answers
333 views

There are $n$ cards which have numbers $1$~$n$ on each. You pick $m$ cards from it, and you don't put it back once you pick from it. Is the probability that their sum is divisible by $k$ always $\...
RDK's user avatar
  • 3,433
1 vote
1 answer
75 views

A Binomial random variable is a generalization of i.i.d. Bernoulli random variables by summing them, arrived at by performing discrete convolution on their distributions. A Multinomial random variable ...
efthimio's user avatar
  • 197
0 votes
1 answer
75 views

I stumbled upon a variation of the Geometric distribution in which a failure may be of one of $n$ types and I wonder if this distribution has a name, what its properties are and what it has been ...
lmyt's user avatar
  • 1
1 vote
0 answers
57 views

As part of an experiment, I independently throw $M$ balls with equal probability into $N$ bins, resulting in $m_i$ balls in the $i$th bin. I then randomly choose $n$ of those $N$ bins and sum the ...
mosdef's user avatar
  • 11
0 votes
0 answers
61 views

I am computing the expected value of this event: suppose we're sampling with replacement from an urn, where the likelihood of red balls is $p$, the likelihood of blue balls is $q$, and the likelihood ...
chibro2's user avatar
  • 1,528
0 votes
1 answer
72 views

There are many questions 1, 2, 3 as well as Condorcet's jury theorem that address finding the probability that a majority vote over a set of responses is correct when responses are generated by $k$ ...
user2757771's user avatar
0 votes
1 answer
76 views

The way Stellaris works is that its AI operates off a script: when the AI is evaluating what to do, it will choose its course of action randomly, with the probability of a certain action being ...
ThexLoneWolf's user avatar
14 votes
3 answers
3k views

I wanted to ask 1) if I've solved this puzzle problem correctly, and 2) if there is a shorter or more elegant approach. There are 43 cookies to be given out at random to 10 children. What is the ...
ctesta01's user avatar
  • 514
4 votes
2 answers
304 views

Given positive integers $n$ and $k$, set $$ S_{n,k}=\sum_{\substack{a_1+a_2+\dots+a_k=2n\\ a_i \in 2\mathbb{N},\,i=1,\ldots,k}}\frac{(2n)!}{a_1!a_2!\dots a_k!}, $$ where $2\mathbb{N}=\{0,2,4,\ldots\}$....
S.Z.'s user avatar
  • 610
1 vote
1 answer
96 views

Suppose that a multinomial distribution has 25 outcomes, the first 24 have chance $\frac{1}{465}$ and the final has $\frac{441}{465}$ chance. Find $n$ the number of trials for this such that the ...
fGDu94's user avatar
  • 4,072
0 votes
1 answer
202 views

I'm trying to find the probability, that in a group of $N$ people, there are no people from at least one district with populations $n_{i}$ (for $i \in \mathbb{N}$ ranging from $0$ to $k$, where $k+1$ ...
Bemciu's user avatar
  • 120

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