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Questions tagged [semiring]

For questions related to semiring. In abstract algebra, a semiring is an algebraic structure similar to a ring, but without the requirement that each element must have an additive inverse.

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For the case of commutative field, we have that each vector space has a basis and even more, each linearly independent set can be completed into a basis. Do we have a same result for general ...
newuser's user avatar
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I usually work with lattices, and one of my professors specializes in this topic as well. However, in the course I am taking, we focus on classical concepts from module theory, rings, and fields, ...
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Let $A$ and $B$ be $n \times n$ matrices with integer coefficients. Consider the tropical multiplication of matrices given component-wise by $$(A\otimes B)_{ij} = \max_{d \in [n]} \left\{ a_{id} + b_{...
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For the purpose of this post, a semiring is an algebraic structure satisfying the axioms of a (unital) ring except the existence of additive inverses. Recall the equivalent characterizations of a ...
Junyan Xu's user avatar
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I am trying to prove the following lemma (originally Prop. A.2) which I found from the paper "Containment of conjunctive queries on annotated relations" by Todd J. Green. Note that although ...
Andrey Yao's user avatar
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1 answer
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Prove that a commutative ring $R$ is a semiprimitive ring if and only if $0$ is the only nilpotent element in $R$. Attempt: I start by noting that a ring is semiprimitive if its Jacobson radical $J(R)$...
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4 votes
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Definitions By a commutative $\textit{semiring}$ (with 1 and without 0), I mean a triple $(S,+,\cdot)$ where $(S,\cdot)$ is a commutative monoid, $(S,+)$ is a commutative semigroup, and $\cdot$ ...
Antoine de Saint Germain's user avatar
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I'm looking into semirings. It is known that is possible to encode derivation over a semiring by considering $d(a+b) = d(a) + d(b)$ and $d(a\cdot b) = d(a) \cdot b + d(b) \cdot a$. Both operations are ...
damianodamiano's user avatar
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1 answer
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Consider the set of length $n$ Boolean vectors, with addition defined as component-wise OR, and multiplication by a boolean scalar value defined by component-wise AND with that scalar, as expected. ...
Michele's user avatar
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A commutative semiring $R$ with exponentiation has an additional operation $R \times R \to R, (a, b) \mapsto a^b$ (called exponentiation), satisfying the following six axioms ($\forall a, b, c \in R$):...
Geoffrey Trang's user avatar
1 vote
1 answer
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A famous result of Funayama and Nakayama states that the congruence lattice of any lattice is a distributive lattice [1]. Also, it can be proved that the lattice is a frame/ complete Heyting algebra 2....
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Some background The natural numbers $\mathsf{Nat}=\{0,1,2,\dots\}$ has the structure of a semiring under addition and multiplication. Write $\mathsf{HFS}$ for the set of all hereditarily finite sets (...
Jim's user avatar
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I know the group completion of a monoid. If we have a semiring $R$, which is in particular a monoid. Then the group completion of $R$ is an abelian group. But how can we define the completion of a ...
Ziqiang Cui's user avatar
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The injective continuous map $h:X\to Y$ is a topological embedding if it is a homeomorphism onto the image of $h$ in $Y$. Let the function $h:X\to Y$ be a topological embedding and let $X=Y$ be a ...
Robert Frost's user avatar
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5 votes
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Mirroring the construction of $\mathbb{Z}$ from $\mathbb{N}$, we can extend a commutative and additively cancellative semiring $A$ to its additive group of differences, $B$, and then define ...
Alex's user avatar
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