0
$\begingroup$

I generated the plot shown below using this code: 

ContourPlot3D[ {x^2 + y^2 == 2.4, x^2 + y^2 - z^2 == 1, x^2 + y^2 + (-Sqrt[4.76] + z)^2 == 2.4, x^2 + y^2 == .5^2}, {x, -10, 10}, {y, -10, 10}, {z, -10, 10}, ContourStyle -> Opacity[.65]]

enter image description here

But what I want to do is create this:

equation1 = x^2 + y^2 == 2.4 constraint1 = -0.5 - Sqrt[4.76] <= z <= -Sqrt[4.76] equation2 = x^2 + y^2 - z^2 == 1 constraint2 = - Sqrt[4.76] <= z <= Sqrt[4.76] equation3 = x^2 + y^2 + (-Sqrt[4.76] + z)^2 == 2.4 constraint3 = Sqrt[4.76] <= z <= Sqrt[5.51] equation4 = x^2 + y^2 == .5^2 constraint4 = Sqrt[5.51] <= z <= Sqrt[5.51] + 1.5

I want to plot the surfaces with the constraints given above, so I can get the figure I designed to print in 3D. I'm really confused about how to integrate the constraints in the plot. Any tips?

Improve this question
$\endgroup$
1

1 Answer 1

Reset to default
1
$\begingroup$

Please try this.

equation1 = x^2 + y^2 == 2.4; constraint1 = -0.5 - Sqrt[4.76] <= z <= -Sqrt[4.76]; equation2 = x^2 + y^2 - z^2 == 1; constraint2 = -Sqrt[4.76] <= z <= Sqrt[4.76]; equation3 = x^2 + y^2 + (-Sqrt[4.76] + z)^2 == 2.4; constraint3 = Sqrt[4.76] <= z <= Sqrt[5.51]; equation4 = x^2 + y^2 == .5^2; constraint4 = Sqrt[5.51] <= z <= Sqrt[5.51] + 1.5; g1 = ContourPlot3D[ Evaluate[equation1], {x, -10, 10}, {y, -10, 10}, {z, constraint1[[1]], constraint1[[3]]}, ContourStyle -> Opacity[.65]]; g2 = ContourPlot3D[ Evaluate[equation2], {x, -10, 10}, {y, -10, 10}, {z, constraint2[[1]], constraint2[[3]]}, ContourStyle -> Opacity[.65]]; g3 = ContourPlot3D[ Evaluate[equation3], {x, -10, 10}, {y, -10, 10}, {z, constraint3[[1]], constraint3[[3]]}, ContourStyle -> Opacity[.65]]; g4 = ContourPlot3D[ Evaluate[equation4], {x, -10, 10}, {y, -10, 10}, {z, constraint4[[1]], constraint4[[3]]}, ContourStyle -> Opacity[.65]]; Show[{g1, g2, g3, g4}, PlotRange -> {{-10, 10}, {-10, 10}, {-10, 10}}]

enter image description here

Improve this answer
$\endgroup$

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.