Foundation
Input: unit circle
The exercise deals with transformations of the unit circle, $(\cos \theta, \sin \theta)$. We start with the unit circle with Hue coloring over the angular range of $(-\pi, \pi)$ as seen below. The green shading denotes a region of right-handed chirality. (As you travel from $-\pi$ to $\pi$, the interior is on the left.)
Transform in 2D
The transformation in two dimensions is $$ \left( \begin{array}{c} \sin \theta\\ \cos \theta \end{array} \right) \Longrightarrow \frac{\sin \theta} {1 + \cos^2 \theta} \left( \begin{array}{c} 1\\ \cos \theta \\ \end{array} \right)$$
The transformation twists the circle into this racetrack figure:
The two lobes separate regions of right-handed chirality (green, left) and left-handed chirality (red, right). The point of the exercise is to show how the unit circle was twisted and mark the chirality of the connected domains.
Transform in 3D
The transformation in three dimensions is $$ \left( \begin{array}{c} \sin \theta\\ \cos \theta \end{array} \right) \Longrightarrow \frac{\sin \theta} {1 + \cos^2 \theta + \cos^4 \theta} \left( \begin{array}{c} 1\\ \cos \theta \\ \cos ^2 \theta \end{array} \right)$$
In Mathematica the transformation is cast as:
fields = Sin[\[Theta]]/(1 + Cos[\[Theta]]^2 + Cos[\[Theta]]^4) {1, Cos[\[Theta]],Cos[\[Theta]]^2}; This code snippet produces the plot, a gently rolling racetrack:
ParametricPlot3D[fields, {\[Theta], -\[Pi], \[Pi]}, ColorFunction -> (Hue[#4 0.8] &), PlotRange -> {1.05 {-1, 1}, 1.05 {-1, 1}}, SphericalRegion -> True, PlotStyle -> Thickness[0.01]] 
Question
How do I shade the two interior zones (left in red, right in green) bound by the curve?
Reference
This post looked promising, but ultimately, I could not use this to solve the problem.
